Find the zeroes of the quadratic polynomial x2+ x -6.
Answers
Answered by
3
Step-by-step explanation:
X2 + 3x -2x -6
= X(x + 3) -2 (x +3)
= (x-2) (x+3) Ans
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Answered by
12
Answer:
p(x) = x² + x - 6
By middle term split
- x² - 3x + 2x - 6
- x (x-3) + 2 (x-3)
- (x-3) (x+2)
Either x - 3 = 0 or x + 2 = 0
- x = 3 or x = (-2)
Hence, 3 and (-2 ) are the zeroes of p(x)
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