Question

Find the zeroes of the quadratic polynomial y^2+7y+10 and verify the relationship between the zeroes and the coefficient

Answer 1

Step-by-step explanation:

${y}^{2} + 7y + 10 = 0 \\ \\ {y}^{2} + 5y + 2y + 10 = 0 \\ \\ y(y + 5) + 2(y + 5) = 0 \\ \\ (y + 2)(y + 5) = 0 \\ \\ y = - 2............y = - 5 \\ \\ let \: \alpha = - 2........... \beta = - 5 \\ \\ \alpha + \beta = \frac{ - b}{a} \\ \\ - 2 - 5 = - 7 \\ \\ - 7 = - 7................proved \\ \\ \alpha \times \beta = \frac{c}{a} \\ \\ ( - 2)( - 5) = 10 \\ \\ 10 = 10.........proved$

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