Question

Find the zeroes of the quadratic polynomial
y = p(x) = x2 - 2x - 8​

Answer 1

Answer:

$x^{2} - 2x - 8$

$x^{2} - 2x + 4x - 8$

$x(x - 2) + 4(x - 2)$

$(x - 2)(x + 4)$

Step-by-step explanation:

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