Find the zeroes of the quadratic polynomial y²-3y-28 and verify the relationship between the zeroes and the coefficients
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Answer:
∝ = -4 , β = 7
Step-by-step explanation:
y² - 3y - 28
a = 1 , b = -3 , c = -28
= y² - 7y + 4y - 28
= y(y - 7) + 4(y - 7)
= (y + 4) (y - 7)
y = -4 , 7
∝ = -4 , β = 7
- b / a = ∝ + β c / a = ∝β
-(-3 / 1) = -4 + 7 -28 / 1 = -4 × 7
3 = 3 -28 = -28
hence verified
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