Find the zeroes of the quadratic
polynomial3x2
-75 and verify the
relationship between the zeroes and
coefficients?
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Step-by-step explanation:
Let f(x) = 3x2 + 5x – 2 By splitting the middle term, we get f(x) = 3x2 + (6 – 1)x – 2 [∵ 5 = 6 – 1 and 2×3 = 6] = 3x2 + 6x – x – 2 = 3x(x + 2) – 1(x + 2) = (3x – 1) (x + 2) On putting f(x) = 0 , we get (3x – 1) (x + 2) = 0 ⇒ 3x – 1 = 0 or x + 2 = 0 x = 1/3 or x = – 2 Thus, the zeroes of the given polynomial 3x2 + 5x – 2 are – 2 and 1/3.
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