Question

Find the zeroes of the quadratic polynomiali) x2-3 ii) x2–2x–8 and verify the relationship between
zeroes and coefficients.​

Answer 1

Answer:

1. The zeroes of x²-3 are -√3,√3

2. The zeroes of x²-2x-8 are 4,-2

Step-by-step explanation:

1. we have,

x²-3=(x+√3)(x-√3)

therefore,

x=-√3,x=√3

sum of zeroes=-√3+√3

=0=-(coefficient of x)/coefficient of x²

=0/1

product of zeroes=(-√3)(√3)

=-3=constant term/coefficient of x²

=-3/1

2. we have,

x²-2x-8=x²-4x+2x-8

=x(x-4)+2(x-4)

=(x-4)(x+2)

therefore,

x=4,x=-2

sum of zeroes=4+(-2)=4-2

=2=-(coefficient of x)/coefficient of x²

=2/1

Product of the zeroes=4(-2)=-8

=constant term/coefficient of x²

=-8/1