Question

find the zeroes of the quadratic polynomials 6x^2-3-7x and verify the relationship between the zeroes and coefficient of the polynomial

Answer 1

let 6x^2 - 3 - 7x be p(x)
to find other zeroes put p(x) = 0
6x^2 - 7x - 3 = 0
6x^2 - [9 - 2]x - 3 = 0
6x^2 - 9x + 2x -3 =0
3x[2x - 3] + 1 [2x -3 ]
(3x + 1) (2x-3)
3x + 1. 2x -3.
x = -1/3 x = 3/2

relationship
sum of zeroes = -1/3 + 3/2
= -6+ 3/2
3/2
product of zeroes = -1/3 x 3/2
= -2/9

hope this helps☺☺