Question

find the zeroes of the quadratic polynomials (8x^2-4)​

Answer 1

$8 {x }^{2} - 4 = 0 \\ 8 {x}^{2} = 4 \\ {x}^{2} = \frac{4}{8} \\ {x}^{2} = \frac{1}{2} \\ x = ±\frac{1}{ \sqrt{2} } = ± \frac{ \sqrt{2} }{2} \\ x = \frac{ \sqrt{2} }{2} , \: - \frac{ \sqrt{2} }{2}$

Two zeroes of the given quadratic polynomial are

$\frac{ \sqrt{2} }{2} \: and \: - \frac{ \sqrt{2} }{2}$