Math, asked by user9172, 1 year ago

Find the zeroes of the quadratic polynomials and verify tge relationship between the zeroes and the coefficients of 3x^2
-x - 4

Answers

Answered by menonology
10

Answer:

3x^2 - x - 4 zeroes are 4/3 and -1

Step-by-step explanation:

3x^2 -x- 4 =0

3x^2 + 3x - 4x -4 = 0

3x(x+1) - 4(x+1) = 0

(3x - 4) (x + 1) = 0

x =4/3, x = -1

Verification :

let α = 4/3

let β = -1

α+β = 4/3 * -1 = 1/3

αβ = -1*4/3 = -4/3

α+β = -b/a = 1/3

αβ = c/a = -4/3

Therefore the zeroes are 4/3 and -1 .

Answered by multigamingff789
1

Answer:

Step-by-step explanation:

3x^2 - x - 4 zeroes are 4/3 and -1

Step-by-step explanation:

3x^2 -x- 4 =0

3x^2 + 3x - 4x -4 = 0

3x(x+1) - 4(x+1) = 0

(3x - 4) (x + 1) = 0

x =4/3, x = -1

Verification :

let α = 4/3

let β = -1

α+β = 4/3 * -1 = 1/3

αβ = -1*4/3 = -4/3

α+β = -b/a = 1/3

αβ = c/a = -4/3

Therefore the zeroes are 4/3 and -1

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