Question

Find the zeroes of the quadratic polynomials given below
x^2+2x+1=0​

Answer 1

$\huge \underline \bold \pink{Solution :}$

${x}^{2} + 2x + 1 = 0 \\ \\ = > {x}^{2} + x + x + 1 = 0 \\ \\ = > x(x + 1) + 1(x + 1) = 0\\ \\ = > {(x + 1)}^{2} = 0 \\ \\ = > x = - 1 \: and \: - 1$

Hence, zeroes of the given quadratic polynomial will be -1 and -1 ✔✔

$\huge \fbox \green{Hope it helps ☺}$

Answer 2

Answer:

-1,-1

Step-by-step explanation:

x^2+x+x+1=0

x(x+1)+1(x+1)=0

(x+1)(x+1)=0

x=-1,-1