Question

find the zeroes of the quadratic polynomials x²+5x+6 and verify the relationship between the zeroes and the cofficients​

Answer 1

Answer:

Zeroes are -2 and -3.

Step-by-step explanation:

p(x)=x^2+5x+6

=x^2+3x+2x+6

=x(x+3)+2(x+3)

(x+2)(x+3)=0

x=-2

x=-3

Zeroes of p(x) are -2 and -3.

Sum of zeroes=-2-3=-5=-b/a

Product of zeroes=(-2)(-3)=6=c/a

Hence verified.

Answer 2

Answer:

The zeroes of polynomial are - 3,-2

Step-by-step explanation:

x²+5x+6=0

x²+3x+2x+6=0

x(x+3)+2(x+3)=0

(x+3)(x+2)=0

x+3=0 or x+2=0

x=-3 or x=-2