Find the zeroes of the quadratic polynomials x2+x-12
verify the relationship between the zeros & its coefficients
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quadratic equations are those equations which having highest power of degree 2
Now, your solution mate.
by factories method
x2 + x - 12
x2 + 4x - 3x - 12
x( x + 4 ) - 3 ( x + 4)
(x - 3) ( x + 4 )
first zero = x - 3
= x = 3
second zero = x + 4
= x = -4
Now, verify the relation
in a quadratic equation
a = 1 , b = 1 , c = -12
sum of zeroes,
alpha + beta = - b / a ( alpha and beta are the zeroes of polynomials)
3 - 4 = -1 / 1
- 1 = -1 ( LHS = RHS)
product of zeroes ,
alpha * beta = c / a
3 * -4 = -12/ 1
-12 = - 12 ( LHS = RHS)
Hope it's help ✌✌✌
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