Question

find the zeroes of the quadratic polynomils 1. 3x^2-x-4​

Answer 1

Answer:

3x^2-4x+3x-4

X(3x-4)+1(3x-4)

(X+1)(3x-4)

X=-1

X=4/3

Answer 2

3x^2-x-4=0

3x^2-4x+3x-4=0

x(3x-4) +1(3x-4)=0

(x+1)(3x-4) = 0

x = -1,4/3