Question

Find the zeroes of the quadric polynomial √3x²-8x+4√3.

Answer 1

Zero's=$\frac{2}{\sqrt{3}},2\sqrt{3}$Note:- check attachment✌

Answer 2

HeRe Is Your Ans ⤵

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➡√3X² - 8X + 4√3 = 0

➡√3X² - 6X - 2X + 4√3 = 0

➡X(√3X - 2) - 2√3(√3X - 2) = 0

➡(X - 2√3) (√3X - 2) = 0

➡X = 2√3 Or X = 2 / √3

Hence , Zeroes Of The Quadratic Polynomial Is

$\fbox{2 \sqrt{3} } \: \: and \: \: \fbox{ \frac{2}{ \sqrt{3} } }$

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$<marquee > hope it helps u$