find the
zeroes of the
the
polynomial
x ²-3
Answers
Answered by
0
Step-by-step explanation:
Given polynomial is x2−3
Here, a=1,b=0 and c=−3
x2−3=(x−3)(x−3)
So, the value of x2−3 is zero when x=3 or x=−3
Threrfore , thr zeroes of x2−3 are 3 and −3.
Now, sum of zeroes =3−3=0=10=a−b
product of zeroes =(3)(−3)=−3=1−3=ac
Hence verified.
Answered by
0
Answer:
Given polynomial is x2−3
Here, a=1,b=0 and c=−3
x2−3=(x−3)(x−3)
So, the value of x2−3 is zero when x=3 or x=−3
Threrfore , thr zeroes of x2−3 are 3 and −3.
Now, sum of zeroes =3−3=0=10=a−b
product of zeroes =(3)(−3)=−3=1−3=ac
Hence verified.
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