Question

find the
zeroes of the
the
polynomial
x ²-3​

Answer 1

Step-by-step explanation:

Given polynomial is x2−3 

Here, a=1,b=0  and c=−3

x2−3=(x−3)(x−3)

So, the value of x2−3 is zero when x=3 or x=−3

Threrfore , thr zeroes of x2−3  are 3  and −3.

Now, sum of zeroes =3−3=0=10=a−b

product  of zeroes =(3)(−3)=−3=1−3=ac

Hence verified.

Answer 2

Answer:

Given polynomial is x2−3 

Here, a=1,b=0  and c=−3

x2−3=(x−3)(x−3)

So, the value of x2−3 is zero when x=3 or x=−3

Threrfore , thr zeroes of x2−3  are 3  and −3.

Now, sum of zeroes =3−3=0=10=a−b

product  of zeroes =(3)(−3)=−3=1−3=ac

Hence verified.