Question

Find the zeroes of the x2-9x+20 are qyadratic polynomial

Answer 1

Answer:

x = 4,5

Step-by-step explanation:

x²-9x+20 = 0

by splitting the middle term

x²-5x-4x+20 = 0

x(x-5)-4(x-5) = 0

(x-5)(x-4) = 0

x = 4,5

pls mark it brainliest.

Answer 2

$\sf \pmb{Answer :}$

x = 4,5

Step-by-step explanation:

x²-9x+20 = 0

by splitting the middle term

x²-5x-4x+20 = 0

x(x-5)-4(x-5) = 0

(x-5)(x-4) = 0

x = 4,5

pls mark it brainliest.