Find the zeroes of the
zeroes of the polynomial,
f(x) = 4√3x^2+ 5x – 2√3
And show that : Sum of zeroes = -5/4√3
Answers
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Answer:
Zeros of the given equation 4 \sqrt{3} x^{2}+5 x-2 \sqrt{3}=0 \text { is } \bold{-\frac{2}{\sqrt{3}} \text { or } \frac{\sqrt{3}}{4}}4
3
x
2
+5x−2
3
=0 is −
3
2
or
4
3
To find:
Find zeros of given equation = ?
Solution:
Given: 4 root 3x square + 5x -2 root 3
The above given equation can be written as under:
4 \sqrt{3} x^{2}+5 x-2 \sqrt{3}=04
3
x
2
+5x−2
3
=0
4 \sqrt{3} x^{2}+8 x-3 x-2 \sqrt{3}=04
3
x
2
+8x−3x−2
3
=0
4 x(\sqrt{3} x+2)-\sqrt{3}(\sqrt{3} x+2)=04x(
3
x+2)−
3
(
3
x+2)=0
(\sqrt{3} x+2)(4 x-\sqrt{3})=0(
3
x+2)(4x−
3
)=0
(\sqrt{3} x+2)=0 \text { or }(4 x-\sqrt{3})=0(
3
x+2)=0 or (4x−
3
)=0
\bold{x=-\frac{2}{\sqrt{3}} \text { or } \frac{\sqrt{3}}{4}}x=−
3
2
or
4
3
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