find the zeroes of thepolynomial x²-3 and verify the relationship between the zeros and the coefficients
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Answered by
0
Answer:
ANSWER
Given polynomial is x
2
−3
Here, a=1,b=0 and c=−3
x
2
−3=(x−
3
)(x−
3
)
So, the value of x
2
−3 is zero when x=
3
or x=−
3
Threrfore , thr zeroes of x
2
−3 are
3
and −
3
.
Now, sum of zeroes =
3
−
3
=0=
1
0
=
a
−b
product of zeroes =(
3
)(−
3
)=−3=
1
−3
=
a
c
Answered by
1
Given x^2-3
Relationship between zeroes and coefficients
Sum of zeroes=(coefficient of x)/coefficient of x^2
=0/1=0
Product of zeroes=constant term/coefficientof x^2
= - 3/1=-3
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