Question

find the zeroes of thepolynomial x²-3 and verify the relationship between the zeros and the coefficients​

Answer 1

Answer:

ANSWER

Given polynomial is x

2

−3

Here, a=1,b=0 and c=−3

x

2

−3=(x−

3

)(x−

3

)

So, the value of x

2

−3 is zero when x=

3

or x=−

3

Threrfore , thr zeroes of x

2

−3 are

3

and −

3

.

Now, sum of zeroes =

3

−

3

=0=

1

0

=

a

−b

product of zeroes =(

3

)(−

3

)=−3=

1

−3

=

a

c

Answer 2

Given x^2-3

Relationship between zeroes and coefficients

Sum of zeroes=(coefficient of x)/coefficient of x^2

=0/1=0

Product of zeroes=constant term/coefficientof x^2

= - 3/1=-3

I hope it's help you

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