Question

find the zeroes of x^2-13​

Answer 1

Step-by-step explanation:

${x}^{2} - 13 = 0 \\ (x + \sqrt{13} )(x - \sqrt{13} ) = 0 \\ x = \sqrt{13} \: or \: x = - \sqrt{13}$

Thank you

Answer 2

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Step-by-step explanation:

$p(x) = {x}^{2} - 13 \\ \\ = > {x}^{2} - ( \sqrt{13} )^{2} \\ \\ = > for \: zeroes \\ \\ p(x) = 0 \\ \\ {x}^{2} - (\sqrt{13} )^{2} = 0 \\ \\(x + \sqrt{13} )(x - \sqrt{13} ) = 0 \\ \\ x = \sqrt{13} \: or \: x = - \sqrt{13}$

Here's The Answer My Friend....

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