Question

Find the zeroes of x^2-15 and also verify the relationship between zeroes and coefficients..(Class 10th)​

Answer 1

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ANSWER

$<b>$

${x}^{2} - 15 = 0 \\ {x }^{2} = 15 \\ x = + - \sqrt{15} \\ x = + \sqrt{15} \: and \: x = \ - \sqrt{15}$

$\underline{verifying relationship}$

let

$\alpha = \sqrt{15} \: \: and \: \: \beta = - \sqrt{15}$

$\alpha + \beta = \sqrt{15} + \: - \sqrt{15 } \\ = 0$

-b/a=0/1

=0

$\alpha + \beta = - b \div a$

$\alpha \beta = \sqrt{15} \times - \sqrt{15} = - 15$

c/a=-15/1=-15

$\alpha \beta = c \div a$

HOPE IT HELPS