Question

Find the zeroes
of (x - 2)² - (x+2)²​

Answer 1

Answer:

(x-2)²-(x+2)²

= (x - 2 + x + 2)(x - 2 - x - 2)

= (2x)(-4)

= -8x

So the zeroes of the polynomial is x = 0

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Answer 2

Answer:

$(x - 2) {}^{2} - (x + 2){}^{2} \\ x {}^{2} + 2 {}^{2} - 2 \times x \times - 2 - x {}^{2} + 2 {}^{2} + 2 \times x \times 2 \\ x {}^{2} + 4 + 4x - x {}^{2} + 4 + 4x \\ 8 + 8x$

Step-by-step explanation:

ok