Question

.Find the zeroes of (x–2)²-(x+2)².

Answer 1

Answer:

Zero of this polynomial = 0

Step-by-step explanation:

(x-2)^2 - (x + 2)^ 2 = 0

(x^2 + 4 - 4x) - (x^2 + 4 + 4x) = 0

x^2 + 4 - 4x - x^2 - 4 - 4x = 0

-8x = 0

x = 0