Question

find the zeroes of x^2-3 and verify the relationship between the zeroes and its coefficient​

Answer 1

Answer:

x² -3 = 0

x² = + -√3

hence the zeros are =√3 and - √3

a = 1

b = 0

c = -3

sum of zeros = -(b) /a

√3 +(-√3) = -(0) / 1

0=0

products of zeros = c/a

√3 × - √3 = 3/ 1

3= 3

Step-by-step explanation:

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