Question

Find the zeroes of x^2-3x+4

Answer 1

Step-by-step explanation:

x² - 3x + 4 = 0

x² - (4 - 1)x + 4 = 0

x² - 4x + x + 4 = 0

x(x - 4).-1(x - 4) = 0

(x - 1)(x - 4) = 0

x - 1 = 0 , x - 4 = 0

x = 1 , x = 4

Answer 2

Answer:

,

Step-by-step explanation:

x2-3x+4=0

x2-4x-x+4=0

x(x-4) -1(x-4) =0

(x-1)(x-4) =0

x-1=0. x-4=0

x=1. x=4