Question

find the zeroes of x^2-3x-m(m-3)​

Answer 1

Let f(x)=x

2

−3x−m(m+3)

Above polynomial can be written as,

f(x)=x

2

−(m+3)x+mx−m(m+3)

=x(x−m−3)+3(x−m−3)

=(x−m−3)(x+m)

To find the zeroes of f(x), put f(x)=0

(x−m−3)(x+m)=0

x−m−3=0 or x=−m

Required zeros are (m+3),−m

Answer 2

Answer:

x²-3x-m(m-3)

alpha*beta=c/a

-m(m-3)

alpha+beta=-b/a

3

If one of your option is

-m, m-3 then this is the correct answer for sure