Question

Find the zeroes of x^2-5/3 and verify the relationship between zeroes and coefficients​

Answer 1

Answer:

x = +√(5/3) and -√(5/3).

Step-by-step explanation:

F(x) = x² - 5/3.

It is in the form of ax² + bx + c = 0. where b = 0.

The zeros of the function are

F(x) = 0

x² - 5/3 = 0

x = +√(5/3) and -√(5/3).

The general equation is ax² + bx + c = 0.

The zeros of the equation are (-b ± √(b² - 4ac))/2a

In the above case, b = 0.

Hence we get generic roots of equation as

(±√(-4ac))/2a

In the given equation a = 1 and c = -5/3.

Hence zeros are ±√(4*5/3)/2*2 = ±√(5/3)