Question

Find the zeroes of x^2-5/3 and verify the relationship between zeroes and coefficients​

Answer 1

${x }^{2} - 5 \div 3 = 0$

${x}^{2} = 5 \div 3$

x=+5/3 and x= -5/3

let them

$\alpha \: and \: \beta$

now here A= 1,B= 0, C= -5/3

Then,

$\alpha + \beta = - b \div a$

0=0 ( by putting value )

$\alpha \times \beta = c \div a$

-25/9 is not equal to -5/3.

So, may be its wrong.

Answer 2

Hey mate!

Here is your solution:

Hope this helps ✌✌