Question

Find the zeroes of x^2-5x+6​

Answer 1

Answer:

Step-by-step explanation:

x2 - 5x + 6 = 0

x2 -3x - 2x + 6 = 0

x(x-3)-2(x-3) = 0

(x-3)(x-2) = 0

x-3 = 0 or x-2 = 0

x = 3 or x= 2

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Answer 2

$x^2-5x+6 = 0\\\\ x^2-3x-2x+6 = 0\\\\ x(x-3)-2(x-3) = 0\\\\ (x-3)(x-2) = 0\\\\x-3 = 0\\\\ x= 3\\\\x-2 = 0\\\\ x = 2\\\\ Therefore,\ the\ zeros\ of\ the\ polynomial\ are\ 2\ and\ 3.$