Question

Find the zeroes of x^2-7x+10

Answer 1

x^2-7x+10
= x^2-5x-2x+10
=x(x-5)-2(x-5)
=(x-5)(x-2)
The zeroes of the polynomial is given by p(x)=0
=(x-5)=0 OR (x-2)=0
=x=5 OR x=2

The zeroes of p(x) are 5 , 2

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Answer 2

$Heya$‼

$Given\:polynomial:x^2-7x+10$

$x^2-7x+10=0$

$x^2-5x-2x+10=0$

$x(x-5)-2(x-5)=0$

$(x-2)(x-5)=0$

$(x-2)=0\:or\:(x-5)=0$

$x=2\:or\:x=5$

Hence, the zeroes of given polynomial are 2 and 5 .