# Find the zeroes of x^2-7x+10

## Answers

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x^2-7x+10

= x^2-5x-2x+10

=x(x-5)-2(x-5)

=(x-5)(x-2)

The zeroes of the polynomial is given by p(x)=0

=(x-5)=0 OR (x-2)=0

=x=5 OR x=2

The zeroes of p(x) are 5 , 2

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= x^2-5x-2x+10

=x(x-5)-2(x-5)

=(x-5)(x-2)

The zeroes of the polynomial is given by p(x)=0

=(x-5)=0 OR (x-2)=0

=x=5 OR x=2

The zeroes of p(x) are 5 , 2

If you find it helpful please mark it as brainliest....

Answered by

0

‼

Hence, the zeroes of given polynomial are 2 and 5 .

Hence, the zeroes of given polynomial are 2 and 5 .

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