Question

Find the zeroes of x^2 +7x+12

Answer 1

Hey friend!!


Here's ur answer...

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${x}^{2} + 7x + 12 \\ = {x}^{2} + 4x + 3x + 12 \\ = x(x + 4) + 3(x + 4) \\ = (x + 3)(x + 4) \\ x = - 3 \\ \\ x = - 4$


So, two zeroes of the given polynomial are - 3 & - 4.


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Hope it may help you....



Thank you :) :))

Answer 2

Here is your solution....!!

I hope it will help you......◆◆◆