Find the zeroes of x^2+x+1
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Step-by-step explanation:
Hey there!
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f (x) = x^2 + x + 1
Where, a = 1 , b = 1 , c =1
One zero = a
Second zero = b
Sum of zeroes ( a + b ) = - b/a = -1 / 1 = -1
Product of zeroes ( a × b ) = c/a = 1 / 1 = 1
We have to find value of , 1 / a + 1 / b
Taking LCM
= a + b / ab
Keeping the values now,
= -1 / 1
= -1
Thus, 1 / a + 1 / b = -1
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Hope it helps...!!!
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