Question

Find the zeroes of x^2 +x - 12

Answer 1

Answer:

The zeroes of given equation, are -4 and 3.

Step-by-step explanation:

x^2 + x - 12 = 0

x^2 + (4-3)x - 12 = 0

x^2 + 4x - 3x - 12 = 0

x(x+4) -3(x+4)= 0

(x+4)(x-3) = 0

x = -4, 3