Question

find the zeroes of (x-2)-(x+2)²

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(and give answer with full and clear solution)
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Answer 1

Answer:

Step-by-step explanation:(x-2)-(x^2+4+4x)=0

x-2-x^2-4-4x=0

-3x-x^2-6=0

x^2+3x+6

Discriminant=b^2-4ac is greater than or equal to zero for real roots

=3^2-4*1*6 should be greater than zero

But it is -15, less than zero , so no real roots