Math, asked by abhijit6343, 10 months ago

Find the zeroes of
X^2+x-p(p+1)

Answers

Answered by cuteprincess69
0

x2+x-p(p+1)=0

x2+(p+1)x-px-p(p+1)=0

x(x+p+1) -p(x+p+1)=0

(x+p+1)(x-p)=0

x=-p-1, p

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