Question

find the zeroes of x^3+3x^2+3x+1​

Answer 1

Step-by-step explanation:

This is an identity.

(a+b)^3=a^3+ 3a^2b +3ab^2 + b^3

Here a=x and b=1

so given polynomial is (x+1)^3

Put (x+1)^3=0

x=-1

Zeroes of given polynomial are -1,-1&-1