Question

find the zeroes of x square plus 2x plus one and verify relationship alpha plus bitta where alpha and beta are it's zeroes

Answer 1

Answer:

X²+2X+1

==> X²+1X+1X+1

==> X(X+1) + 1(X+1)

==> X + 1 = 0  ;  X+1 = 0

==> X = -1 ; -1

            OR

X²+2X+1

==> (X)²+2.X.1 + (1)²

==> (X+1)²

SO, (X+1)(X+1)

==> X = -1 ,-1