find the zeroes of x square plus 2x plus one and verify relationship alpha plus bitta where alpha and beta are it's zeroes
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Answer:
X²+2X+1
==> X²+1X+1X+1
==> X(X+1) + 1(X+1)
==> X + 1 = 0 ; X+1 = 0
==> X = -1 ; -1
OR
X²+2X+1
==> (X)²+2.X.1 + (1)²
==> (X+1)²
SO, (X+1)(X+1)
==> X = -1 ,-1
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