Question

Find the zeroes of "x²+2x+1" and verify the relationship between the zeroes and the coefficients??​

Answer 1

Answer:

x^2+2x+1=0

x^2+x+x+1=0

x(x+1)+1(x+1)=0

(x+1)(x+1)=0

Therefore x=-1 or x=-1

Now you can verify after this using

alpha+beta=-b/a

alpha*beta=c/a

where alpha and beta are zeroes of the given polynomial.

Hope it will help you

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Answer 2

x²+2x+1 = 0

=> x²+x+x+1 = 0

=> x(x+1) +1(x+1) = 0

=> (x+1)(x+1) = 0

Thus (x+1)= 0

x = -1

The two zeroes are -1 and -1.

Let a= -1 and b = -1

a+b = -1-1

= -2

= -2/1

= - coefficient of x/coefficient of x²

ab = (-1)(-1)

= 1

= constant / coefficient of x²

Hence the relationship is verified.

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