Question

find the zeroes of x²-2x

Answer 1

Answer:

$\mathfrak{Quadratic\:Formula:}$

$\bf{\frac{-b \pm \sqrt{b^{2} - 4ac}}{2a}}$

=》 a = 1, b = (-2), c = 0

=》 $\bf{\frac{2 \pm \sqrt{2^{2} - 4(1)(0)}}{2(1)}}$

=》 $\bf{\frac{2 \pm \sqrt{4}}{2}}$

=》 $\bf{\frac{2 \pm 2}{2}}$

=》 x = 0, 2

Therefore, zeroes = 0 and 2