Question

find the zeroes of x²-2x-15 and verify the relationship b/w zeroes and co - efficients​

Answer 1

Step-by-step explanation:

x2-2x-15 ;a=1,b=-2,c=-15

by split in the middle term method we have:

x2-2x-15=0

x2-5x+3x-15=0

x(x-5)+3(x-5)=0

(x-5)(X+3)=0

x-5=0;X=5=alpha

X+3=0;X=-3=bheta

sum of zeros= alpha+bheta= -b/a

5-3=-(-2/1)

2=2

product of zeros=alpha*bheta=c/a

5*-3=-15/1

-15=-15

hence verified