Question

find the
zeroes of x²-2x-8 and hence
verify the
the relation between zeroes and
coefficient ​

Answer 1

Answer:

x=4, -2

Step-by-step explanation:

${x }^{2} - 4x + 2x - 8 = 0$

$x(x - 4) + 2(x - 4) = 0$

$(x + 2)(x - 4) = 0$

$x = - 2 \: \: x = 4$

Answer 2

x^2-2x-8

x^2-4x+2x-8

x(x-4) +2(x-4)

(x-4) (x+2)

x=4 x=-2

α=4 β=-2

Relation between zeros are

α+β=2

4-2=2

2=2

αβ=-8

4*-2=-8

-8=-8