Math, asked by shagunchauhan0304, 5 months ago

find the zeroes of x²-36​

Answers

Answered by kulkarninishant346
2

Step-by-step explanation:

⭐Hey here is your answer...⭐

x^2 - 36 = 0

(x)^2 - (6)2

(x + 6)(x - 6) = 0

either ,

x +6 = 0

x = -6

or ,

x -6 = 0

x = 6

I HOPE IT WILL HELP YOu ☺️☺️

Thnx for asking ur question ✌️✌️

Answered by architagupta83
3

Answer:

6and(-6) are the zeroes

Step-by-step explanation:

x²-36=0

(x+6)(x-6)=0 : (a²-b²= ( a+b)( a-b)) )

x+6=0

x= -6

and

x-6=0

x=6

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