Question

find the zeroes of x²-7

Answer 1

x² - 7 = 0

Write both terms in perfect square:

x² - (√7)² = 0

Apply a² - b² = (a + b)(a - b)

(x - √7) (x + √7) = 0

Apply zero product property:

x = √7 or -√7

Answer 2

❤❤Here is your answer ✌ ✌

$\huge {\red {\bold {Answer}}}$


$x {}^{2} - 7 \\( x ){}^{2} - \sqrt{7} \\ (x - \sqrt{} 7)(x + \sqrt{} 7) \\ x - \sqrt{} 7 = 0 \\ x = \sqrt{} 7 \\ x + \sqrt{7} = 0 \\ x = - \sqrt{7}$