Find the zeroes of x2-9
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x2-9
x^2 - 3^2
(x-3)(x+3)
x-3=0 x=3
x+3=0 x=-3
Zeroes are 3 and -3
x^2 - 3^2
(x-3)(x+3)
x-3=0 x=3
x+3=0 x=-3
Zeroes are 3 and -3
Answered by
0
Here the zeros are=+3 &-3
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