FIND THE ZEROES OF X²-9 AND X²-7x+12
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x²-9
x²= 9
x=√3
x=±3
zeros of polynomial of x²-9 = 3,-3
x²-7x+12
x²-4x-3x+12
(x²-4x) (-3x+12)
x(x-4) -3(x-4)
(x-4)(x-3)
x = 4,3
zeros of the polynomial are x²-7x+12 are 4,3
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