Math, asked by nobinthomas02, 2 months ago

find the zeroes of x²-root 3x-6 plz fast

Answers

Answered by ItzAnu2108
2

Answer:-

 {x}^{2}  -  \sqrt{3} x - 6 \\  {x}^{2}  - 2 \sqrt{3} x +  \sqrt{3} x - 6 \\ x(x - 2 \sqrt{3} ) +  \sqrt{3} (x - 2 \sqrt{3} ) \\ (x +  \sqrt{3} )(x - 2 \sqrt{3} )

u'r done!!

Thnx✌️♥️~

Answered by Rashi0906
0

 {x}^{2}  -  \sqrt{3} x - 6 \\  {x}^{2}   - 2 \sqrt{3} x +  \sqrt{3} x - 6 \\ x(x - 2 \sqrt{3} ) +  \sqrt{3} (x - 2 \sqrt{3} ) \\ (x - 2 \sqrt{3} )(x +  \sqrt{3} )

Thnx✌️♥️~

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