find the zeroes of x²-root 3x-6 plz fast
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u'r done!!
Thnx✌️♥️~
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x² - √3x - 6
x² - 2√3x + √3x - 6
x(x - 2√3) + √3(x - 2√3)
(x - 2√3)(x + √3)
x = 2√3 or -√3
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Answered by
1
x² - √3x - 6
x² - 2√3x + √3x - 6
x(x - 2√3) + √3(x - 2√3)
(x - 2√3)(x + √3)
x = 2√3 or -√3
▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬
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