Question

Find the zeroes of x2+route2x-4

Answer 1

x² + √2 x -4 =0
⇒ x² +2√2 x - √2 x - 4=0
⇒x(x+2√2) - √2(x +2√2) =  0
⇒(x+2√2)(x -√2) = 0
⇒(x+2√2) = 0 or (x-√2) = 0

⇒x = -2√2 or √2
Zeroes of the polynomial are -2√2 and √2