Question

find the zeroes of x²-x-12 *

Answer 1

x²-x-12

x²-(4-3)x-12=0

x²-4x+3x-12=0

x(x-4) +3(x-4) =0

(x-4) (x+3)=0

:.x-4=0 or , x+3=0

x=4 x=-3

gm❤

Answer 2

Answer:

-3, 4

Step-by-step explanation:

write -x as -4x+3x

make sure sum is -1 and product is -12 which are the coefficients this is logic for any sum