Question

find the zeroes of x2+x+12​

Answer 1

Answer:

Step-by-step explanation:e have to find the zeroes of the quadratic polynomial, x² + x - 12.

             

x² + x - 12 = 0

⇒x² + 4x - 3x - 12 = 0

⇒x(x + 4) - 3(x + 4) = 0

⇒(x - 3)(x + 4) = 0

⇒x = 3, -4

sum of zeroes = - coefficient of x/coefficient of x²

sum of zeroes = 3 - 4 = -1

- coefficient of x/coefficient of x² = -1/1 = -1

LHS = RHS

product of zeroes = constant/coefficient of x²

product of zeros = 3 × -4 = -12

constant/coefficient of x² = -12/1 = -12

LHS = RHS

hence verified