Question

Find the Zeroes
P(x) 6x²-3-7x
of the quadratic polynomial​

Answer 1

Step-by-step explanation:

$p(x) = 6x²-3-7x$

$\: \: \: \: \: \: \: \: \: \: = 6x²-7x-3$

$\: \: \: \: \: \: \: \: \: \: = 6x²-9x+2x-3$

$\: \: \: \: \: \: \: \: \: \: = 3x(2x-3)+1(2x-3)$

$\: \: \: \: \: \: \: \: \: \: = (2x-3)(3x+1)$

$If p(x) = 0$

$\implies (2x-3)(3x+1) = 0$

$\implies (2x-3) = 0 \: \: \: \& \: \: \: (3x+1) = 0$

$\implies 2x = 3 \: \: \: or \: \: \: 3x = -1$

$\implies x = \frac{3}{2} \: \: \: or \: \: \: x = \frac{-1}{3}$